How 0.1N and 0.05M bromine solution are equivalent

Please note the following concepts and calculations,

The molarity of a solute in a solution is defined as the number of solute moles present in a one-liter volume of solution (which means 1 g mole per liter of a solution is 1 molar solution).

The normality of a solute in a solution is defined as the number of solute equivalents present in a one-liter volume of solution (Which means 1 g equivalent per liter of a solution is 1 normal solution).

In simple language, when 1 g molecular weight of bromine is dissolved in water and made into 1-liter volume, it will be 1 Molar solution. (The molecular weight of Bromine is 159.80)

When 1 g equivalent weight of bromine is dissolved in water and made into 1-liter volume, it will be 1 Normal solution. (The equivalent weight of bromine is 79.90)

Thus, when 159.80 g (1 g molecular weight) of bromine is dissolved in water and made into a 1-liter volume, it will be 1 Molar bromine solution.

Thus, when 15.980 g of bromine is dissolved in water and made into a 1-liter volume, it will be 0.1 Molar bromine solution.

When (15.980/2) = 7.990 g of bromine is dissolved in water and made into a 1-liter volume, it will be 0.05 Molar bromine solution.

When 79.90 g (1 g equivalent weight) of bromine is dissolved in water and made into a 1-liter volume, it will be 1 Normal bromine solution.

And, when (79.90/10) =7.990 g of bromine is dissolved in water and made into a 1-liter volume, it will be 0.1 Normal bromine solution.

This means that 7.990 g of bromine in 1 liter of water will be 0.1 Normal solution OR 0.05 Molar bromine solution.

Therefore, 0.1 Normal bromine solution and 0.05 Molar bromine solution are equal.Both are the same.

The reason is that the equivalent weight of bromine is half of its molecular weight.

Hope, I have clarified the matter.

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